3w^2-6w=1120

Solution for 3w^2-6w=1120 equation:

3w^2-6w=1120

We move all terms to the left:

3w^2-6w-(1120)=0

a = 3; b = -6; c = -1120;
Δ = b2-4ac
Δ = -62-4·3·(-1120)
Δ = 13476
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{13476}=\sqrt{4*3369}=\sqrt{4}*\sqrt{3369}=2\sqrt{3369}$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{3369}}{2*3}=\frac{6-2\sqrt{3369}}{6}
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{3369}}{2*3}=\frac{6+2\sqrt{3369}}{6}
$